1946 Iowa Senate election

The 1946 Iowa State Senate elections took place as part of the biennial 1946 United States elections. Iowa voters elected state senators in 23 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate. A statewide map of the 50 state Senate districts in the 1946 elections is provided by the Iowa General Assembly here. The primary election on June 3, 1946 determined which candidates appeared on the November 5, 1946 general election ballot. Following the previous election, Republicans had control of the Iowa state Senate with 45 seats to Democrats' 5 seats.

1946 Iowa Senate election

The 1946 Iowa State Senate elections took place as part of the biennial 1946 United States elections. Iowa voters elected state senators in 23 of the state senate's 50 districts. State senators serve four-year terms in the Iowa State Senate. A statewide map of the 50 state Senate districts in the 1946 elections is provided by the Iowa General Assembly here. The primary election on June 3, 1946 determined which candidates appeared on the November 5, 1946 general election ballot. Following the previous election, Republicans had control of the Iowa state Senate with 45 seats to Democrats' 5 seats.