1864 United States presidential election in Rhode Island
The 1864 United States presidential election in Rhode Island took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president. Rhode Island voted for the National Union candidate, Abraham Lincoln, over the Democratic candidate, George B. McClellan. Lincoln won the state by a margin of 24.48%.
1864 United States presidential election in Rhode Island
The 1864 United States presidential election in Rhode Island took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose four representatives, or electors to the Electoral College, who voted for president and vice president. Rhode Island voted for the National Union candidate, Abraham Lincoln, over the Democratic candidate, George B. McClellan. Lincoln won the state by a margin of 24.48%.
has abstract
The 1864 United States preside ...... e state by a margin of 24.48%.
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country
start date
1864-11-08
title
1864United States presidential electionin Rhode Island
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Wikipage page ID
53,965,969
page length (characters) of wiki page
Wikipage revision ID
1,019,254,479
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after election
after party
National Union Party
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before election
before party
Republican Party
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country
Rhode Island
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election date
1864-11-08
election name
home state
image
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image size
x200px
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map caption
County Results
Lincoln
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map image
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map size
next election
next year
nominee
Abraham Lincoln
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ongoing
no
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party
Democratic Party
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National Union Party
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percentage
popular vote
previous election
previous year
running mate
Andrew Johnson
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title
President
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type
presidential
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wikiPageUsesTemplate
subject
comment
The 1864 United States preside ...... e state by a margin of 24.48%.
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label
1864 United States presidential election in Rhode Island
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