United States presidential election in Minnesota, 1988
The 1988 United States presidential election in Minnesota took place on November 8, 1988, as part of the 1988 United States presidential election. Voters chose ten representatives, or electors to the Electoral College, who voted for President and Vice President. Minnesota was won by Democrat Michael Dukakis, Governor of Massachusetts, with 52.91% of the popular vote over Republican Vice President George H.W. Bush's 45.90%, a victory margin of 7.01%.
United States presidential election in Minnesota, 1988
The 1988 United States presidential election in Minnesota took place on November 8, 1988, as part of the 1988 United States presidential election. Voters chose ten representatives, or electors to the Electoral College, who voted for President and Vice President. Minnesota was won by Democrat Michael Dukakis, Governor of Massachusetts, with 52.91% of the popular vote over Republican Vice President George H.W. Bush's 45.90%, a victory margin of 7.01%.
has abstract
The 1988 United States preside ...... t voted Republican since 1972.
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country
start date
1988-11-08
title
United States presidential electionin Minnesota, 1988
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Wikipage page ID
38,376,744
Wikipage revision ID
735,303,561
after election
after party
Republican Party
before election
before party
Republican Party
home state
map caption
County Results
map size
next election
United States presidential election in Minnesota, 1992
next year
nominee
party
Minnesota Democratic-Farmer-Labor Party
Republican Party
percentage
popular vote
previous election
United States presidential election in Minnesota, 1984
previous year
running mate
title
type
subject
comment
The 1988 United States preside ...... 0%, a victory margin of 7.01%.
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label
United States presidential election in Minnesota, 1988
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