The 1948 American League tie-breaker game was a one-game extension to Major League Baseball's (MLB) 1948 regular season, played between the Cleveland Indians and Boston Red Sox to determine the winner of the American League (AL) pennant. The game was played on October 4, 1948, at Fenway Park in Boston, Massachusetts. It was necessary after both teams finished the season with identical win–loss records of 96–58. This was the first-ever one-game playoff in the AL, and the only one prior to 1969 when the leagues were split into divisions.