United States presidential election in Ohio, 1840
The 1840 United States presidential election in Ohio took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose twenty-one representatives, or electors to the Electoral College, who voted for President and Vice President. Ohio voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Ohio by a margin of 8.53%.
United States presidential election in Ohio, 1840
The 1840 United States presidential election in Ohio took place between October 30 and December 2, 1840, as part of the 1840 United States presidential election. Voters chose twenty-one representatives, or electors to the Electoral College, who voted for President and Vice President. Ohio voted for the Whig candidate, William Henry Harrison, over Democratic candidate Martin Van Buren. Harrison won Ohio by a margin of 8.53%.
has abstract
The 1840 United States preside ...... won Ohio by a margin of 8.53%.
@en
country
start date
1840-12-02
thumbnail
title
United States presidential electionin Ohio, 1840
@en
Wikipage page ID
41,442,248
Wikipage revision ID
738,473,043
after color
after election
after party
before color
before election
before party
Democratic Party
candidate
William Henry Harrison
home state
homestate
next election
United States presidential election in Ohio, 1844
next year
nominee
William Henry Harrison
party
percentage
popular vote
previous election
United States presidential election in Ohio, 1836
previous year
running mate
title
type
votes
vp name
vp state
subject
comment
The 1840 United States preside ...... won Ohio by a margin of 8.53%.
@en
label
United States presidential election in Ohio, 1840
@en